Examveda

The energy of 9800J was used to lift the 70kg weight at which height the weight was lifted?

A. 14m

B. 140m

C. -140m

D. -14m

Answer: Option A

Solution (By Examveda Team)

To find the height, we use the formula for gravitational potential energy:

Potential Energy (PE) = m × g × h

Where:

PE = 9800 J (Energy used)

m = 70 kg (Mass of the object)

g = 10 m/s² (Acceleration due to gravity, commonly used in numerical problems)

h = ? (Height)

Substituting the given values:

9800 = 70 × 10 × h

9800 = 700h

h = 9800 ÷ 700 = 14 m

Therefore, the 70 kg object was lifted to a height of 14 metres.

Note: Options with negative height are incorrect because the object is being lifted upward, so the height must be positive.

This Question Belongs to Physics GK Chapter Wise >> Work, Energy And Power

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Comments (2)

  1. Sikander Panchal
    Sikander Panchal:
    3 weeks ago

    PE= 9800J
    Mass= 70 kg
    g=10 m/s²
    H=?
    PE=mgh
    9800= 70×10×H
    H=9800/70×10
    H=14m

  2. Darshan Kdacchu
    Darshan Kdacchu:
    2 months ago

    P.E=mgh

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