The expected discharge to be obtained from an open well sunk in coarse sand is 0.0059 cumec. If the working depression head of the well is 3 m, the minimum diameter of the well, is
A. 2 m
B. 2.25 m
C. 2.50 m
D. 3.00 m
Answer: Option D
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Q=KiA ; i=3m; A = 0.785d^2; K=1 Q=0.0059m^3/sec=0.0059*3600=21.24m^3/hr.
21.24=1*3*0.785*d^2,
d^2=(21.24)/(3*0.785)=9.0191,
d=3m.
Explanation