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The expression, $$\Delta {\text{G}} = {\text{nRT}}.l{\text{n}}\frac{{{{\text{P}}_2}}}{{{{\text{P}}_1}}},$$    gives the free energy change

A. With pressure changes at constant temperature

B. Under reversible isothermal volume change

C. During heating of an ideal gas

D. During cooling of an ideal gas

Answer: Option A

Solution(By Examveda Team)

We know, the property relation:
$$dG = vdp - sdT$$
Which is valid for both reversible and irreversible process since it is a property relation. when the system undergoes isothermal change $$dT = 0$$
$$\eqalign{ & {\text{So, }}dG = vd \cr & \Rightarrow dG = \frac{{nRT}}{P}dP\left( {{\text{for, ideal gas}}} \right) \cr} $$
On, integration
$$ \Rightarrow \Delta G = nRT.ln\frac{{{P_2}}}{{{P_1}}}$$
So, for a system containing ideal gas and undergoing isothermal change of volume or pressure this expression is valid.

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Comments ( 1 )

  1. Prasanna Gusidi
    Prasanna Gusidi :
    4 years ago

    Very nice explanation

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