The first three terms of an A.P. respectively are 3y – 1, 3y + 5 and 5y + 1. Then, y equals
A. -3
B. 4
C. 5
D. 2
Answer: Option C
Solution (By Examveda Team)
2 (3y + 5) = 3y – 1 + 5y + 1(If a, b, c are in A.P., b – a = c – b ⇒ 2b = a + c)
⇒ 6y + 10 = 8y
⇒ 10 = 2y
⇒ y = 5
This Question Belongs to Arithmetic Ability >> Progressions
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