The following currents are measured in the same direction in a three-branch parallel circuit: 200 mA, 340 mA, and 700 mA. The value of the current into the junction of these branches is
A. 200 mA
B. 540 mA
C. 1.24 A
D. 900 mA
Answer: Option C
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At the junction , by kirchoffs law
200+340+700=I
So I=1240 Ma or 1.24 amps