The graph of 2x + 1 = 0 and 3y - 9 = 0 intersect at the point?
A. $$\left( { - \frac{1}{2}, - 3} \right)$$
B. $$\left( { - \frac{1}{2},3} \right)$$
C. $$\left( {\frac{1}{2}, - 3} \right)$$
D. None of these
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & 2x + 1 = 0 \cr & \Leftrightarrow x = \frac{{ - 1}}{2}{\text{ }} \cr & 3y - 9 = 0 \cr & \Leftrightarrow y = \frac{9}{3} = 3 \cr & \therefore \left( {x,y} \right) = \left( {\frac{{ - 1}}{2},3} \right) \cr & {\text{Point of intersection}} \cr} $$This Question Belongs to Arithmetic Ability >> Algebra
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