The group delay function τ(ω) is related to phase function φ(ω) as
A. $$\tau \left( \omega \right) = - \frac{{d\phi \left( \omega \right)}}{{d\omega }}$$
B. $$\tau \left( \omega \right) = \frac{{d\phi \left( \omega \right)}}{{d{\omega ^2}}}$$
C. $$\tau \left( \omega \right) = - \frac{{{d^2}\phi \left( \omega \right)}}{{d{\omega ^2}}}$$
D. $$\tau \left( \omega \right) = \frac{{{d^2}\phi \left( \omega \right)}}{{d\omega }}$$
Answer: Option A
This Question Belongs to Electronics And Communications Engineering >> Electromagnetic Field Theory
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