The internal energy of an incompressible fluid depends upon its

Solution (By Examveda Team)

$$dU = CvdT - \left[ {P + T\left( {\frac{{\left( {\frac{{\partial V}}{{\partial T}}} \right)P}}{{\left( {\frac{{\partial V}}{{\partial P}}} \right)T}}} \right)dV} \right]$$       Since in case of incompressible fluid
$$\eqalign{ & dV = 0 \cr & \Rightarrow dU = {C_V}dT \cr} $$
So, internal energy is a function of temperature only.