The internal energy of an incompressible fluid depends upon its
A. Pressure
B. Temperature
C. Both A & B
D. Neither A nor B
Answer: Option B
Solution(By Examveda Team)
$$dU = CvdT - \left[ {P + T\left( {\frac{{\left( {\frac{{\partial V}}{{\partial T}}} \right)P}}{{\left( {\frac{{\partial V}}{{\partial P}}} \right)T}}} \right)dV} \right]$$ Since in case of incompressible fluid$$\eqalign{ & dV = 0 \cr & \Rightarrow dU = {C_V}dT \cr} $$
So, internal energy is a function of temperature only.
Related Questions on Chemical Engineering Thermodynamics
A. Maxwell's equation
B. Thermodynamic equation of state
C. Equation of state
D. Redlich-Kwong equation of state
Henry's law is closely obeyed by a gas, when its __________ is extremely high.
A. Pressure
B. Solubility
C. Temperature
D. None of these
A. Enthalpy
B. Volume
C. Both A & B
D. Neither A nor B
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