The lengths of two sides of a parallelogram are 3 cm and 10 cm. What is the sum of the squares of the diagonals of the parallelogram?
A. 218 cm2
B. 109 cm2
C. 169 cm2
D. 206 cm2
Answer: Option A
Solution (By Examveda Team)

AC2 + BD2 = 2(AB2 + BC2)
AC2 + BD2 = 2(102 + 32) = 218
Related Questions on Geometry
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is

A. 30°
B. 40°
C. 20°
D. 70°


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