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The lines 2x + y = 5 and x + 2y = 4 intersect at the point?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 2x + y = 5..............(i) \cr
& x + 2y = 4..............(ii) \cr
& {\text{Multiply equation (ii) by 2}} \cr
& 2x + 4y = 8............(iii) \cr} $$
Now subtracting equation (i) from (iii)
$$\eqalign{ & {\text{ }}2x + 4y = 8 \cr & \mathop {}\limits_ - 2x\mathop + \limits_ - \,\,y\, = 5 \cr & \overline {\underline {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3y = 3{\text{ }}} } \cr & y = 1 \cr & x = 2 \cr & \therefore {\text{Intersection point = }}\left( {2,1} \right) \cr} $$
Now subtracting equation (i) from (iii)
$$\eqalign{ & {\text{ }}2x + 4y = 8 \cr & \mathop {}\limits_ - 2x\mathop + \limits_ - \,\,y\, = 5 \cr & \overline {\underline {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3y = 3{\text{ }}} } \cr & y = 1 \cr & x = 2 \cr & \therefore {\text{Intersection point = }}\left( {2,1} \right) \cr} $$
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