The lines 2x + y = 5 and x + 2y = 4 intersect at the point?
A. (1, 2)
B. (2, 1)
C. (2, 0)
D. (0, 2)
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & 2x + y = 5..............(i) \cr & x + 2y = 4..............(ii) \cr & {\text{Multiply equation (ii) by 2}} \cr & 2x + 4y = 8............(iii) \cr} $$Now subtracting equation (i) from (iii)
$$\eqalign{ & {\text{ }}2x + 4y = 8 \cr & \mathop {}\limits_ - 2x\mathop + \limits_ - \,\,y\, = 5 \cr & \overline {\underline {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3y = 3{\text{ }}} } \cr & y = 1 \cr & x = 2 \cr & \therefore {\text{Intersection point = }}\left( {2,1} \right) \cr} $$
Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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