The magnetic field (in A/m) inside a long solid cylindrical conductor of radius a = 0.1 m is $$\overrightarrow {\bf{H}} = \frac{{{{10}^4}}}{r}\left[ {\frac{1}{{{\alpha ^2}}}\sin \left( {\alpha r} \right) - \frac{r}{\alpha }\cos \left( {\alpha r} \right)} \right]\hat \phi ,$$ where, $$\alpha = \frac{\pi }{{2a}}.$$ What is the total current (in ampere) in the conductor?
A. $$\frac{\pi }{{2a}}$$
B. $$\frac{{800}}{\pi }$$
C. $$\frac{{400}}{\pi }$$
D. $$\frac{{300}}{\pi }$$
Answer: Option B

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