The moisture content of sludge is reduced from 90% to 80% in a sludge digestion tank. The percentage decrease in the volume of sludge, is
A. 25 %
B. 50 %
C. 10 %
D. 5 %
Answer: Option B
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Initial = 90%.
Final = 80%.
V2/V1 = (100 - Initial) / (100- Final).
= 100 - 90 / 100 - 80,
= 10 / 20,
= 1/2.
For % multiply by 100.
Ans is 50%.