The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is
A. $$\frac{{{\text{m}}{{\text{r}}^2}}}{2}$$
B. $$\frac{{{\text{m}}{{\text{r}}^2}}}{4}$$
C. $$\frac{{{\text{m}}{{\text{r}}^2}}}{6}$$
D. $$\frac{{{\text{m}}{{\text{r}}^2}}}{8}$$
Answer: Option A

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