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The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is

A. $$\frac{{{\text{m}}{{\text{r}}^2}}}{2}$$

B. $$\frac{{{\text{m}}{{\text{r}}^2}}}{4}$$

C. $$\frac{{{\text{m}}{{\text{r}}^2}}}{6}$$

D. $$\frac{{{\text{m}}{{\text{r}}^2}}}{8}$$

Answer: Option A


This Question Belongs to Mechanical Engineering >> Engineering Mechanics

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If a number of forces are acting at a point, their resultant is given by

A. $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2}$$

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