The moment of inertia of a thin rod of mass 'm' and length '$$l$$', about an axis through its centre of gravity and perpendicular to its length is
A. $$\frac{{{\text{m}}{l^2}}}{4}$$
B. $$\frac{{{\text{m}}{l^2}}}{6}$$
C. $$\frac{{{\text{m}}{l^2}}}{8}$$
D. $$\frac{{{\text{m}}{l^2}}}{{12}}$$
Answer: Option D

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