The Nernst equation for the reaction, A2+ + 2e- → B, in terms of the free energy change is
A. ΔG = ΔG° + 2.303 RT log $$\frac{{\left[ B \right]}}{{\left[ A \right]}}$$
B. ΔG = ΔG° - 2.303 RT log $$\frac{{\left[ B \right]}}{{\left[ A \right]}}$$
C. -ΔG = -ΔG° + 2.303 RT log $$\frac{{\left[ B \right]}}{{\left[ A \right]}}$$
D. ΔG = -ΔG° + 2.303 RT log $$\frac{{\left[ B \right]}}{{\left[ A \right]}}$$
Answer: Option A
This Question Belongs to Engineering Chemistry >> Electrochemistry
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