The number of degree of freedom for an azeotropic mixture of ethanol and water in vapour-liquid equilibrium, is
A. 3
B. 1
C. 2
D. 0
Answer: Option B
Solution(By Examveda Team)
For an azeotropic mixture since the composition of a constituent remains same in vapour and liquid one of the variable to define the system reduces.So, $$f = C - \emptyset + 2$$
Given number of components $$= 2,$$ number of phases $$= 2$$
So, degree of freedom $$= 1$$
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F=2-2+2
F=2
then degree of freedom is 2
Its correct option is C
wait 2-2+2=2 how did we get 1