The probable error can be calculated by
A. $$0.6745\left[ {\frac{{1 - {r^2}}}{{\sqrt N }}} \right]$$
B. $$0.6745\sqrt {\frac{{d{x^2}d{y^2}}}{N}} $$
C. $$0.6320 \times \frac{N}{{\sqrt {dx} }}$$
D. $$0.6325 \times \frac{N}{{\sqrt {d{x^2}d{y^2}} }}$$
Answer: Option A
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