Examveda

The quantum efficiency η for the photo detector is
Where,
Iph = Average photocurrent
Pe = Average incident optical power
hc/λ = Incident photon energy

A. $$\frac{{{{\text{I}}_{{\text{ph}}}}}}{{{{\text{P}}_0}}}$$

B. $$\frac{{{{\text{I}}_{{\text{ph}}}}{\text{/e}}}}{{{{\text{P}}_{\text{0}}}{\text{/(hc/}}\lambda {\text{)}}}}$$

C. $$\frac{{{{\text{P}}_{\text{0}}}}}{{{{\text{I}}_{{\text{ph}}}}}}$$

D. $$\frac{{{{\text{P}}_{\text{0}}}{\text{/(hc/}}\lambda {\text{)}}}}{{{{\text{I}}_{{\text{ph}}}}{\text{/e}}}}$$

Answer: Option B


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