The quantum efficiency η for the photo detector is
Where,
Iph = Average photocurrent
Pe = Average incident optical power
hc/λ = Incident photon energy
A. $$\frac{{{{\text{I}}_{{\text{ph}}}}}}{{{{\text{P}}_0}}}$$
B. $$\frac{{{{\text{I}}_{{\text{ph}}}}{\text{/e}}}}{{{{\text{P}}_{\text{0}}}{\text{/(hc/}}\lambda {\text{)}}}}$$
C. $$\frac{{{{\text{P}}_{\text{0}}}}}{{{{\text{I}}_{{\text{ph}}}}}}$$
D. $$\frac{{{{\text{P}}_{\text{0}}}{\text{/(hc/}}\lambda {\text{)}}}}{{{{\text{I}}_{{\text{ph}}}}{\text{/e}}}}$$
Answer: Option B
This Question Belongs to Electronics And Communications Engineering >> Electronic Devices And Circuits
Join The Discussion