The reflex angle between the hands of a clock at 10.25 is:
A. 180º
B. $${\text{192}}{\frac{1}{2}^ \circ }$$
C. 195º
D. $${\text{197}}{\frac{1}{2}^ \circ }$$
Answer: Option D
Solution(By Examveda Team)
Angle traced by hour hand in $$\frac{{125}}{{12}}$$ hrs$$\eqalign{ & = {\left( {\frac{{360}}{{12}} \times \frac{{125}}{{12}}} \right)^ \circ } \cr & = 312{\frac{1}{2}^ \circ } \cr} $$
Angle traced by minute hand in 25 min
$$\eqalign{ & = {\left( {\frac{{360}}{{60}} \times 25} \right)^ \circ } \cr & = {150^ \circ } \cr} $$
$$\eqalign{ & \therefore {\text{Reflex angle}} \cr & = {360^ \circ } - {\left( {312\frac{1}{2} - 150} \right)^ \circ } \cr & = {360^ \circ } - 162{\frac{1}{2}^ \circ } \cr & = 197{\frac{1}{2}^ \circ } \cr} $$
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Comments ( 7 )
Related Questions on Clock
The reflex angle between the hands of a clock at 10.25 is:
A. 180º
B. $${\text{192}}{\frac{1}{2}^ \circ }$$
C. 195º
D. $${\text{197}}{\frac{1}{2}^ \circ }$$
A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:
A. 145º
B. 150º
C. 155º
D. 160º
A. $$59\frac{7}{{12}}$$ min. past 3
B. 4 p.m.
C. $$58\frac{7}{{11}}$$ min. past 3
D. $$2\frac{3}{{11}}$$ min. past 4
What is 125/2
192.5 degree
@Xojiakbar
This is true answer
Angel between them is 162.5 but
Reflex angle is 360-162.5=197.5
Therefore this is correct answer.
Formula-
a - angle
a = 30×hr-11/2×min
Hr = 10
Min = 25
a = 30×10-11/2×25
= 300-275/2
= 162.5
Reflex angle = 360-162.5 =197.5
angle = 30 H - 11M/2
= 30×10 - 11×25/2
300-275/2
300-137.5
= 162.5
Reflex angle =360 - 162.5 = 197.5
false answer
true answer=162.5
Good question.