The root mean square speed of molecules of a gas is equal to (where, m = mass of the molecule K = Boltzman's constant, T = absolute temperature)
A. $$\sqrt {\frac{{2{\text{KT}}}}{{\text{m}}}} $$
B. $$\sqrt {\frac{{3{\text{KT}}}}{{\text{m}}}} $$
C. $$\sqrt {\frac{{6{\text{KT}}}}{{\text{m}}}} $$
D. $$\frac{{3{\text{KT}}}}{{\text{m}}}$$
Answer: Option B
Solution (By Examveda Team)
empirical relation:Root mean square speed $$ = \sqrt {\frac{{3KT}}{m}} $$
Whereas average velocity $$ = \sqrt {\frac{{8KT}}{{\pi m}}} $$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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