The sewage discharge in a detritus tank of a treatment plant is 576 litres/sec with flow velocity of 0.2 m/sec. If the ratio of width to depth is 2, the depth is
A. 100 cm
B. 110 cm
C. 120 cm
D. 150 cm
Answer: Option C
This Question Belongs to Civil Engineering >> Waste Water Engineering
Join The Discussion
Comments ( 1 )
Related Questions on Waste Water Engineering
The effluent of a septic tank is
A. Fit for discharge into any open drain
B. Foul and contains dissolved and suspended solids
C. As good as that from a complete treatment
D. None of these
The bottom of the sewage inlet chamber of septic tanks, is provided an outward slope
A. 1 in 5
B. 1 in 10
C. 1 in 15
D. 1 in 20
Drop manholes are the manholes
A. Without entry ladders
B. Without manhole covers
C. With depths more than 3.5 m
D. Having drains at different levels
Given.
Q = 576 lit/sec, means Q = 0.576 m^3/sec because (1 m^3 = 1000 lit).
Also given v = 0.2 m/sec.
We know that Q = A*V,
So A = Q/V = 0.576/0.2 = 2.88 m^2,
Also given width/depth = 2 means b = 2*d.
So A = b*d = 2.88, given b = 2d.
So 2d*d = 2.88. So d^2 = 1.44.
So d =under root 1.44, d = 1.2 m = 1.2*100 = 120 cm.