The side BC of a triangle ABC is extended to the point D. If ∠ACD = 132° and ∠B = $$\frac{4}{7}$$∠A, then the measure of ∠A is equal to:

Solution (By Examveda Team)

$$\eqalign{ & \angle {\text{B}} = \frac{4}{7}\angle {\text{A}} \cr & \frac{{\angle {\text{B}}}}{{\angle {\text{A}}}} = \frac{4}{7} \cr} $$
By exterior angle theorem
7x + 4x = 132°
11x = 132°
x = 12°
∠A = 7 × 12° = 84°