The solution for the differential equation $$\frac{{{\text{dy}}}}{{{\text{dx}}}} = {{\text{x}}^2}{\text{y}}$$ with the condition that y = 1 at x = 0 is
A. $${\text{y}} = {{\text{e}}^{\frac{1}{{2{\text{x}}}}}}$$
B. $$\ln \left( {\text{y}} \right) = \frac{{{{\text{x}}^3}}}{3} + 4$$
C. $$\ln \left( {\text{y}} \right) = \frac{{{{\text{x}}^2}}}{2}$$
D. $${\text{y}} = {{\text{e}}^{\frac{{{{\text{x}}^3}}}{3}}}$$
Answer: Option D

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