The solution of $$\frac{{{\text{dy}}}}{{{\text{dx}}}} = {{\text{y}}^2}$$ with initial value y(0) = 1 bounded in the interval
A. $$ - \infty \leqslant {\text{x}} \leqslant \infty $$
B. $$ - \infty \leqslant {\text{x}} \leqslant 1$$
C. $${\text{x}} < 1,\,{\text{x}} > 1$$
D. $$ - 2 \leqslant {\text{x}} \leqslant 2$$
Answer: Option C

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