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The standard free energies of formation of H2S(g) and CdS(s) at 1000°C are -49.0 kJ/mol and -127.2 kJ/mol respectively. Use these data to predict whether H2(g) will reduce CdS(s) to metallic Cd at this temperature.

A. ΔG = -78.2 kJ/mol and H2 reduces CdS

B. ΔG = -39.1 kJ/mol and H2 reduces CdS

C. ΔG = 0 kJ/mol and the reaction is at equilibrium

D. ΔG = 78.2 kJ/mol and the reaction is not feasible

Answer: Option D


This Question Belongs to Engineering Chemistry >> Chemical Thermodynamics

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Related Questions on Chemical Thermodynamics

For the reaction, N2(g) + 3H2(g) → 2NH3(g)
compute the entropy change (in J/K/mol) for the process and comment on the sign of the property.

Data Species
S°(J/K/mol)
NH3(g)
192.3
N2(g)
191.5
H2(g)
130.6

A. ΔS° = -37.65 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction

B. ΔS° = -198.7 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction

C. ΔS° = -31.25 J/K/mol; negative sign indicates that there is a decrease in the gaseous species during the reaction

D. ΔS° = +31.25 J/K/mol; positive sign indicates that the reaction is spontaneous