The standard state of a gas (at a given temperature) is the state in which fugacity is equal to
A. Unity
B. Activity
C. Both A & B
D. Neither A nor B
Answer: Option C
Solution(By Examveda Team)
The standard state of an gas is taken as ideal gas state where the fugacity is equal to pressure and the pressure is usually taken as $$1,$$ similarly the activity under ideal state is equal to $$1$$ since the activity is the ratio of fugacity at conditions of our interest to the fugacity at standard state and we are taking the standard state as pressure $$= 1$$So, activity = fugacity = 1.
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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