The steady-state response of a network to the excitation Vcos(ωt + φ) may be found in three steps. The first two steps are as follows:
1. Determining the response of the network to the excitation e^jωt.
2. Multiplying the above response by $$\overline {\text{V}} $$ = Ve^jφ.
The third step is

A. finding the complex conjugate of the expression after step 2

B. finding the magnitude of the expression after step 2

C. finding the real part of the expression after step 2

D. finding the imaginary part of the expression after step 2

Answer: Option C