The sum of 4digit number containing the digit 2 4 6 8 without repetition them

Thanks.. Gopal mittal for ur answer...

Hi
This isthe problem answer
4p4=24
Sn=n÷2{a+l}
S24=24÷2{2468+8642}
S24=24÷2{11110}
S24=12×11110
S24=133320.

The most simple way is
Total sum=(sum of digit)(n-1)! × 1111
=(2+4+6+8) (4-1)! × 1111
=(20)(3)!×1111
=(20)(3×2×1)×1111
=20×6×1111
=133320

Karan rohilla thanks for the solution
Can u explain that addition form...i mean the last part of the solution

2468
2486
2648
2684
2846
2864

8246
8264
8426
8462
8624
+8642

We find that each column has: six 2's, six 4's, six 6's, six 8's.

The total of each column is 6*2 + 6*4 + 6*6 + 6*8 = 120

Hence, the addition has the form:

000120
001200
012000
+120000
------------
133320

Therefore, the sum is: 133,320

Hope I helped : )