The switch in the circuit in the figure is in position P for a long time and then moved to position Q at time t = 0.
The value of $$\frac{{dv\left( t \right)}}{{dt}}{\text{at }}t = {0^ + }$$ is
A. 3 V/s
B. -5 V/s
C. -3 V/s
D. 0 V/s
Answer: Option C
This Question Belongs to Electronics And Communications Engineering >> Network Theory And Analysis
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