The term to be added to 121a2 + 64b2 to make a perfect square is?
A. 176 ab
B. 276 a2b
C. 178 ab
D. 188 b2a
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\text{121}}{a^2} + 64{b^2} \cr & = {\left( {11a} \right)^2} + {\left( {8b} \right)^2} + 2 \times 11a \times 8b \cr & = {\left( {11a + 8b} \right)^2} \cr} $$∴ So, term added to make perfect square = 176 ab
This Question Belongs to Arithmetic Ability >> Algebra
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