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The term to be added to 121a2 + 64b2 to make a perfect square is?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{121}}{a^2} + 64{b^2} \cr
& = {\left( {11a} \right)^2} + {\left( {8b} \right)^2} + 2 \times 11a \times 8b \cr
& = {\left( {11a + 8b} \right)^2} \cr} $$
∴ So, term added to make perfect square = 176 ab
∴ So, term added to make perfect square = 176 ab
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