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The theoretical minimum work required to separate one mole of a liquid mixture at 1 atm, containing 50 mole % each of n- heptane and n- octane into pure compounds each at 1 atm is
Answer & Solution
Correct Answer:
Option
B
Entropy of mixing is
$$\eqalign{ & = - R\sum {{X_i}\ln {x_i}} \cr & = - R\left[ {0.5\,\ln \,0.5 + 0.5\,\ln \,0.5} \right] \cr} $$
Since, work $$ = T\Delta S = - RT\,\ln \,0.5.$$
$$\eqalign{ & = - R\sum {{X_i}\ln {x_i}} \cr & = - R\left[ {0.5\,\ln \,0.5 + 0.5\,\ln \,0.5} \right] \cr} $$
Since, work $$ = T\Delta S = - RT\,\ln \,0.5.$$
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