The transfer function of a first-order process is given by Y( s )R( s ) = G( s ) = K s + 1 Then the impulse response to an impulse strength of 5 is

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Control Systems

The transfer function of a first-order process is given by $$\frac{{Y\left( s \right)}}{{R\left( s \right)}} = G\left( s \right) = \frac{K}{{\tau s + 1}}$$
Then the impulse response to an impulse strength of 5 is

A) $$y\left( t \right) = \frac{{KA}}{\tau }{e^{ - \frac{{5t}}{\tau }}}$$ B) $$y\left( t \right) = \frac{{5K}}{\tau }{e^{ - \frac{{5t}}{\tau }}}$$ C) $$y\left( t \right) = \frac{{5K}}{\tau }{e^{ - \frac{t}{\tau }}}$$ D) $$y\left( t \right) = \frac{{KA}}{\tau }{e^{ - \frac{t}{\tau }}}$$

Answer & Solution

Correct Answer: Option C

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The transfer function of a first-order process is given by $$\frac{{Y\left( s \right)}}{{R\left( s \right)}} = G\left( s \right) = \frac{K}{{\tau s + 1}}$$ Then the impulse response to an impulse strength of 5 is

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Related Questions on Control Systems

The transfer function of a first-order process is given by $$\frac{{Y\left( s \right)}}{{R\left( s \right)}} = G\left( s \right) = \frac{K}{{\tau s + 1}}$$
Then the impulse response to an impulse strength of 5 is