The transfer function of a first-order process is given by $$\frac{{Y\left( s \right)}}{{R\left( s \right)}} = G\left( s \right) = \frac{K}{{\tau s + 1}}$$
Then the impulse response to an impulse strength of 5 is

A. $$y\left( t \right) = \frac{{KA}}{\tau }{e^{ - \frac{{5t}}{\tau }}}$$

B. $$y\left( t \right) = \frac{{5K}}{\tau }{e^{ - \frac{{5t}}{\tau }}}$$

C. $$y\left( t \right) = \frac{{5K}}{\tau }{e^{ - \frac{t}{\tau }}}$$

D. $$y\left( t \right) = \frac{{KA}}{\tau }{e^{ - \frac{t}{\tau }}}$$

Answer: Option C