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The value of $$\frac{{{{\left( {4.6} \right)}^4} + {{\left( {5.4} \right)}^4} + {{\left( {24.84} \right)}^2}}}{{{{\left( {4.6} \right)}^2} + {{\left( {5.4} \right)}^2} + 24.84}}$$ is:
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 4.6 = b \cr
& 5.4 = a \cr
& \frac{{{b^4} + {a^4} + {a^2}{b^2}}}{{{a^2} + {b^2} + ab}} \cr
& = \frac{{\left( {{a^2} + {b^2} + ab} \right)\left( {{a^2} + {b^2} - ab} \right)}}{{{a^2} + {b^2} + ab}} \cr
& = {a^2} + {b^2} - ab \cr
& = {\left( {a - b} \right)^2} + ab \cr
& = {\left( {5.4 - 4.6} \right)^2} + 24.84 \cr
& = {0.8^2} + 24.84 \cr
& = 25.48 \cr} $$
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