The value of $$\frac{{48.3 \times \left[ {{{\left( {4.95} \right)}^2} + 4.95 \times 13.25} \right]}}{{\left[ {{{\left( {12.55} \right)}^2} - {{\left( {5.65} \right)}^2}} \right] \times 19.8}} = ?$$
A. 17.5
B. 0.175
C. 1.75
D. 175
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & \frac{{48.3 \times \left[ {{{\left( {4.95} \right)}^2} + 4.95 \times 13.25} \right]}}{{\left[ {{{\left( {12.55} \right)}^2} - {{\left( {5.65} \right)}^2}} \right] \times 19.8}} \cr & = \frac{{48.3 \times 4.95\left[ {4.95 + 13.25} \right]}}{{\left( {12.55 + 5.65} \right)\left( {12.55 - 5.65} \right) \times 19.8}} \cr & = \frac{{48.3 \times 4.95 \times 18.2}}{{18.2 \times 6.9 \times 19.8}} \cr & = \frac{7}{4} \cr & = 1.75 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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