The value of $$\frac{1}{{1 + \sqrt 2 + \sqrt 3 }} + $$   $$\frac{1}{{1 - \sqrt 2 + \sqrt 3 }}$$   is = ?

A. $$\sqrt 2 $$

B. $$\sqrt 3 $$

C. 1

D. $$4\left( {\sqrt 3 + \sqrt 2 } \right)$$

Answer: Option C

Solution(By Examveda Team)

$$\eqalign{ & \frac{1}{{1 + \sqrt 2 + \sqrt 3 }} + \frac{1}{{1 - \sqrt 2 + \sqrt 3 }} \cr & = \frac{1}{{1 + \sqrt 3 + \sqrt 2 }} + \frac{1}{{1 + \sqrt 3 - \sqrt 2 }} \cr & = \frac{{1 + \sqrt 3 - \sqrt 2 + 1 + \sqrt 3 + \sqrt 2 }}{{{{\left( {1 + \sqrt 3 } \right)}^2} - {{\left( {\sqrt 2 } \right)}^2}}} \cr & = \frac{{2 + 2\sqrt 3 }}{{4 + 2\sqrt 3 - 2}} \cr & = \frac{{2 + 2\sqrt 3 }}{{2 + 2\sqrt 3 }} \cr & = 1 \cr} $$