The value of $$\frac{{4{x^3} - x}}{{\left( {2x + 1} \right)\left( {6x - 3} \right)}}$$ when x = 9999 is?
A. 1111
B. 2222
C. 3333
D. 6666
Answer: Option C
Solution(By Examveda Team)
$$\eqalign{ & x = 9999{\text{ }}\left( {{\text{ Given}}} \right) \cr & \frac{{4{x^3} - x}}{{\left( {2x + 1} \right)\left( {6x - 3} \right)}} \cr & = \frac{{x\left( {4{x^2} - 1} \right)}}{{3\left( {2x + 1} \right)\left( {2x - 1} \right)}} \cr & = \frac{{x\left( {4{x^2} - 1} \right)}}{{3\left( {4{x^2} - 1} \right)}} \cr & = \frac{x}{3} \cr & \therefore \frac{{9999}}{3} = 3333 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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