The value of $$\frac{{4{x^3} - x}}{{\left( {2x + 1} \right)\left( {6x - 3} \right)}}$$    when x = 9999 is?

$$\eqalign{ & x = 9999{\text{ }}\left( {{\text{ Given}}} \right) \cr & \frac{{4{x^3} - x}}{{\left( {2x + 1} \right)\left( {6x - 3} \right)}} \cr & = \frac{{x\left( {4{x^2} - 1} \right)}}{{3\left( {2x + 1} \right)\left( {2x - 1} \right)}} \cr & = \frac{{x\left( {4{x^2} - 1} \right)}}{{3\left( {4{x^2} - 1} \right)}} \cr & = \frac{x}{3} \cr & \therefore \frac{{9999}}{3} = 3333 \cr} $$