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This question belongs to Mechanical Engineering Engineering Thermodynamics

Engineering Thermodynamics

?

The value of the product of molecular weight and the gas characteristic constant for all the gases in M.K.S. unit is

A) 29.27 kgfm/mol °K B) 8314 kgfm/mol °K C) 848 kgfm/mol °K D) 427 kgfm/mol °K

Answer & Solution

Correct Answer: Option C

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Question posted by Examveda

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8 Comments

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AMAR BRANWAL 6 years ago

Since, 1 kgf m = 9.81 Nm or 1Nm= (1/9.81)kgf m
And R= 8314 J/mol K or 8314 Nm/mol K
Therefore, R = (8314 /9.81) kgf m/mol k
Thus R= 848 kgf m/mol K

AMAR BRANWAL 6 years ago

1 kgf m = 9.81 Nm
Therefore 1 Nm = 1/9.81 kgf m
Now, Value of R = 8314J/mol K or 8314 Nm/mol K
Hence, R = (8314 × 1/9.81)kgf m/mole K
Therefore R= 848 kgf m/mole K

Mohd Rashid 6 years ago

B is correct option

Ajaj Alam 7 years ago

Option C is right but unit is wrong.
It should be kgf-m/kmol-k

Pratik Sonawane 7 years ago

Option B is correct

Vijay Mori 8 years ago

Hi

Vijay Mori 8 years ago

Hi

Vijay Mori 8 years ago

Hi

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