The value of $${\left( {{x^{b + c}}} \right)^{b - c}}$$ $$ \times $$ $${\left( {{x^{c + a}}} \right)^{c - a}}$$ $$ \times $$ $${\left( {{x^{a + b}}} \right)^{a - b}}$$   is?
A. 1
B. 2
C. -1
D. 0
Answer: Option A
Solution(By Examveda Team)
$$\eqalign{ & {\left( {{x^{b + c}}} \right)^{b - c}} \times {\left( {{x^{c + a}}} \right)^{c - a}} \times {\left( {{x^{a + b}}} \right)^{a - b}}\left( {x \ne 0} \right) \cr & = {x^{{b^2} - {c^2}}} \times {x^{{c^2} - {a^2}}} \times {x^{{a^2} - {b^2}}} \cr & = {x^{{b^2} - {c^2} + {c^2} - {a^2} + {a^2} - {b^2}}} \cr & = {x^0} \cr & = 1 \cr} $$Related Questions on Algebra
If $$p \times q = p + q + \frac{p}{q}{\text{,}}$$ then the value of 8 × 2 is?
A. 6
B. 10
C. 14
D. 16
A. $$1 + \frac{1}{{x + 4}}$$
B. x + 4
C. $$\frac{1}{x}$$
D. $$\frac{{x + 4}}{x}$$
A. $$\frac{{20}}{{27}}$$
B. $$\frac{{27}}{{20}}$$
C. $$\frac{6}{8}$$
D. $$\frac{8}{6}$$
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