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The velocity ratio in case of an inclined plane inclined at...

This question belongs to Mechanical Engineering Engineering Mechanics
Engineering Mechanics
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The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is

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Correct Answer: Option A
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4 Comments
Kankan Kishore
Kankan Kishore 5 years ago
Velocity Ratio = Effort application distance/Load raised distance
For this problem effort is applied vertically i.e. effort application distance is the perpendicular length of the triangle whose hypotenuse is the length of the inclined plane (making theta angle with horizontal). Load is raised through that length of the hypotenuse. Thus,
Perpendicular distance / hypotenuse will give sin(theta).
M TEJA
M TEJA 6 years ago
use the resolution of forces method.
an inclined line can be resolved into 2 components.
NIKHIL Kumar
NIKHIL Kumar 7 years ago
If weight is resolved w sin θ acts parallel to plane
Then
P= w sinθ
MA = W/P = 1/ sin θ = Cosecθ


So answer is d
Yasridatanth Kummari
Yasridatanth Kummari 7 years ago
Explain
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