The width of a settling tank with 2 hour detention period for treating sewage 378 cu m per hour, is
A. 5 m
B. 5.5 m
C. 6.5 m
D. 7 m
Answer: Option D
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Q=378,
T=2hr,
Vol=QT=756m3.
Let depth D=4m.
Area B*L=Vol/D=189m2.
We know L=4B.
A=L*B=4B2=189m2.
So, B=6.87m~7m.
T = Q/BxL.
BxL = 378/2 = 189,
Usually L = 4B,
Therefore 4B^2 = 189,
B = 6.87~ 7m.
how?