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There are 20 couples in a party. Every person greets every person except his or her spouse. People of the same sex shake hands and those of opposite sex greet each other with a Namaste (It means bringing one's own palms together and raising them to the chest level). What is the total number of handshakes and Namaste's in the party?

A. 760

B. 1140

C. 780

D. 720

Answer: Option B

Solution(By Examveda Team)

There are 20 men and 20 women.
When a man meets a woman, there are two Namastes, whereas when a man meets a man (or a woman) there is only 1 handshake.
Number of handshakes,
= 2 × 20C2 (men and women ) = 2 × 190 = 380

For a number of Namastes, Every man does 19 Namastes (to the 20 women excluding his wife) and they respond in the same way.
Number of Namastes
= 2 × 20 × 19
= 760

Total number of Namastes and Handshake
= 760 + 380
= 1140

This Question Belongs to Arithmetic Ability >> Permutation And Combination

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Comments ( 3 )

  1. VIPUL TIWARI
    VIPUL TIWARI :
    6 years ago

    why at last 19x20x2

  2. Examveda
    Examveda :
    6 years ago

    Answer Updated. Kindly review it.

  3. Deeksha Chandwani
    Deeksha Chandwani :
    6 years ago

    2*20C2 should be 380 not 760.??
    answer should be A.

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