There are only three bound states for a particle of mass m in a one-dimensional potential well of the form shown in the figure. The depth V0 of the potential satisfies

A. $$\frac{{2{\pi ^2}{\hbar ^2}}}{{m{a^2}}} < {V_0} < \frac{{9{\pi ^2}{\hbar ^2}}}{{2m{a^2}}}$$
B. $$\frac{{{\pi ^2}{\hbar ^2}}}{{m{a^2}}} < {V_0} < \frac{{2{\pi ^2}{\hbar ^2}}}{{m{a^2}}}$$
C. $$\frac{{2{\pi ^2}{\hbar ^2}}}{{m{a^2}}} < {V_0} < \frac{{8{\pi ^2}{\hbar ^2}}}{{m{a^2}}}$$
D. $$\frac{{2{\pi ^2}{\hbar ^2}}}{{m{a^2}}} < {V_0} < \frac{{50{\pi ^2}{\hbar ^2}}}{{m{a^2}}}$$
Answer: Option C
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