There are two containers, with one containing 4 red and 3 green balls and the other containing 3 blue and 4 green balls. One ball is drawn at random from each container. The probability that one of the balls is red and the other is blue will be
A. $$\frac{1}{7}$$
B. $$\frac{9}{{49}}$$
C. $$\frac{{12}}{{49}}$$
D. $$\frac{3}{7}$$
Answer: Option C
This Question Belongs to Engineering Maths >> Probability And Statistics
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A. E(XY) = E(X) E(Y)
B. Cov (X, Y) = 0
C. Var (X + Y) = Var (X) + Var (Y)
D. E(X2Y2) = (E(X))2 (E(Y))2
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