This program will print the string #include< stdio h> int main()

This program will print the string #include< stdio h> int main()...

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This program will print the . . . . . . . . string.

#include<stdio.h>
 
int main()
{
    int fd[2];
    char buff[11];
    if (pipe(fd) != 0)
        perror("pipe");
    write(fd[1],"Example",11);
    lseek(fd[0],0,3);
    read(fd[0],buff,11);
    printf("%s\n",buff);
    return 0;
}

A. "Example"

B. "exam"

C. "linux"

D. none of the mentioned

Answer: Option A

This Question Belongs to Computer Science >> Linux

This program will print the . . . . . . . . string.

`#include<stdio.h> int main() { int fd[2]; char buff[11]; if (pipe(fd) != 0) perror("pipe"); write(fd[1],"Example",11); lseek(fd[0],0,3); read(fd[0],buff,11); printf("%s\n",buff); return 0; }`

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This program will print the string #include< stdio h> int main()...

This program will print the . . . . . . . . string. #include<stdio.h> int main() { int fd[2]; char buff[11]; if (pipe(fd) != 0) perror("pipe"); write(fd[1],"Example",11); lseek(fd[0],0,3); read(fd[0],buff,11); printf("%s\n",buff); return 0; }

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This program will print the . . . . . . . . string.

`#include<stdio.h> int main() { int fd[2]; char buff[11]; if (pipe(fd) != 0) perror("pipe"); write(fd[1],"Example",11); lseek(fd[0],0,3); read(fd[0],buff,11); printf("%s\n",buff); return 0; }`