Three 47 Ω resistors are connected in parallel across a 110 volt source. The current drawn from the source is approximately

Solution (By Examveda Team)

First, understand what a parallel circuit means. In a parallel circuit, all the resistors are connected side-by-side to the voltage source. This means the voltage across each resistor is the same, which in this case is 110 volts.

Next, we need to find the total resistance of the parallel combination. Since we have three identical resistors (47 Ω each) in parallel, we can use a simplified formula: Total Resistance (R_total) = Resistance of one resistor / Number of resistors.

So, R_total = 47 Ω / 3 ≈ 15.67 Ω. The total resistance is less than the resistance of any single resistor when they are in parallel.

Now, we can use Ohm's Law to find the total current drawn from the source. Ohm's Law states: Current (I) = Voltage (V) / Resistance (R).

Therefore, I = 110 V / 15.67 Ω ≈ 7.02 A.

Looking at the options, 7.06 A (Option D) is the closest answer to our calculated value. Therefore, option D is the correct answer.

Therefore, Option D: 7.06 A is the correct answer.