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Three gentlemen and three ladies are candidates for two vacancies. A voter has to vote for two candidates. In how many ways can one cast his vote?

Answer & Solution
Correct Answer: Option D
There are 6 candidates and a voter has to vote for any two of them.
So, the required number of ways is,
$$\eqalign{ & { = ^6}{{\text{C}}_2} \cr & = \frac{{6!}}{{2! \times 4!}} \cr & = 15 \cr} $$
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4 Comments
2K18/ME/192 SANCHIT
2K18/ME/192 SANCHIT 5 years ago
I feel that the answer is wrong
since after casting 1 vote, he has 5 candidates to choose from
so the answer should be 30 (6C1*5C1)
as per the solution given the person is straightaway choosing 2 people out of 6 which is wrong.
Noah Johnson
Noah Johnson 8 years ago
this is wrong.! There will be 30 different ways to vote.
M1M2, M1M3, M2M1, M2M3, M3M1, M3M2
W1W2, W1W3, W2W1, W2W3, W3W1, W1W2,
W1M1, W1M2,W1M3, W2M1, W2M2,W2M3,
W3M1, W3M2,W3M3, M1W1, M1W2, M1W3,
M2W1, M2W2, M2W3, M3W1, M3W2, M3W3
Juhi Shah
Juhi Shah 10 years ago
1 gentlemen and(*) 1 lady or (+) 2 gentleman
or(+) 2 ladies =
=3c1*3c1 + 3c2 +3c2
=9+6+6
=15
Mrunali Gedam
Mrunali Gedam 11 years ago
WHY TAKE 4! ?