Translational kinetic energy of molecules of an ideal gas is proportional to (where, T = absolute temperature of the gas)
A. T
B. $$\sqrt {\text{T}} $$
C. T2
D. $$\frac{1}{{\sqrt {\text{T}} }}$$
Answer: Option A
Solution(By Examveda Team)
Translational kinetic energy of an ideal gas is given by $$ = \frac{3}{2}KT.$$This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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