ΔABC is isosceles having AB = AC and ∠A = 40°. Bisectors PO and OQ of the exterior angles ∠ABD and ∠ACE formed by producing BC on both sides, meet at O. Then the value of ∠BOC is
A. 70°
B. 110°
C. 80°
D. 55°
Answer: Option A
Solution (By Examveda Team)
AB = AC
∴ ∠B = ∠C
∠B = $$\frac{{{{180}^ \circ } - {{40}^ \circ }}}{2}$$
∠B = 70°
∠B = ∠C = 70°
∠BOC = 90° - $$\frac{{\angle {\text{A}}}}{2}$$
= 90° - 20°
= 70°
This Question Belongs to Arithmetic Ability >> Geometry
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